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27 May, 11:05

If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = - 2. Give only the numerical answer.

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  1. 27 May, 12:56
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    Dx/dt=3

    y=3x^3-2x

    dy/dt = (9x^2) (dx/dt) - 2 (dx/dt)

    When x = - 2

    dy/dt = (9 (-2) ^2) (3) - 2 (3)

    =36 (3) - 6

    =102
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