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21 June, 03:05

In the figure, we must apply a force of magnitude 80.0 N to hold the block stationary at x = - 3.0 cm. From that position, we then slowly move the block so that our force does + 7.0 J of work on the spring-block system; the block is then again stationary. What are the block's positions? ((a) positive and (b) negative)

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  1. 21 June, 03:23
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    I think it is a) positive as:

    Work done = force * distance

    So distance = work done / force

    = 7 / 80

    = 0.0875m so 8.75 cm

    Then: - 3 + 8 = 5 so the position is X = + 5cm
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