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19 September, 17:48

If f (x) = x^2-x and g (x) = 1/x and h (x) is defined with the expressions below, arrange the values of h' (1) from smallest to largest. 1) h (x) = f (x) - g (x) 2) h (x) = f (x) g (x) 3) h (x) = f (g (x))

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  1. 19 September, 19:01
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    F (x) = x²-x

    g (x) = 1/x

    1) h (x) = f (x) - g (x) = (x²-x) - (1/x) = (x³-x²) / x (x≠0) = >

    2) h (x) = f (x). g (x) = (x²-x). (1/x) = x (x²-1)

    3) h (x) = f (g (x)) = (1/x) ² - (1/x)
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