If ƒ (x) = 2x 2 3, then ƒ (x - 1) = 2x 2 4x 5. true or false

Since you didn't write the signs, I have to make some suggestions, this is what I assume:

If ƒ (x) = 2x²+3, then ƒ (x - 1) = 2x²+4x+5.

So, how much is ƒ (x-1?)

it would be = 2 (x-1) ²+3 = 2 (x-1) (x-1) + 3 = 2 (x²-2 x+1) + 3 = 2x²-4x+2+3=2x²-4 x+5

So, yes, if my assumption is correct, then it's true!