Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward

The givens are as follows:

initial velocity (vi) = 6 m/sec

acceleration = - 9.8 m/sec^2 (the negative sign refers to the direction)

final velocity (v) = 1.1 m/sec

initial position (xi) = 0 meters

Now, we will use the equations of motion to get the displacement as follows:

v = vi + at

1.1 = 6 - 9.8t

9.8t = 6-1.1 = 4.9

t = 0.5 sec

x = xi + vit + 0.5at^t

x = 0 + (6) (0.5) + 0.5 (-9.8) (0.5) ^2

x = 1.775 meters