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28 September, 20:04

If the recessive allele for an x-linked recessive disease in humans has a frequency of 0.02 in the population, what proportion of individuals in the population will have the disease? assume that the population is 50 : 50 male:female.

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  1. 28 September, 22:43
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    To have the disease, males need only one copy of the affected X.

    So, the frequency of affected males will be the frequency of the disease allele = 0.02

    Females must inherit two copies and be homozygotes, so the frequency of affected females will be the double of frequency of the disease allele = (0.02)

    Since the ratio between female and male is 50:50 that is half of the population is male and half female

    Then the overall frequency of the disease will be,

    (0.5) (0.02) + (0.5) (0.0004) = 0.01 + 0.0002

    Thus, the frequency of affected individuals in this population is 0.0102.
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