What is the molarity of 40.0 grams of sodium hydroxide in 1.50 L of solution

Formula: Molarity = Amount of substance (in moles) / Volume of solution (in litres)

40.0⋅g / 40 ⋅ g⋅ mol - 1 : (1.50⋅L) = 0.667 - 1 sodium hydroxide.

The Molarity of 40 grams of Sodium Hydroxide in 1.50L of solution is 0.667 mol*L-1