N labrador retrievers, black coat (b) is dominant to brown coat (b) and normal vision (n) is dominant to blindness (n). the genes for coat color and blindness are on separate chromosomes. you cross a dog that is heterozygous for coat color and vision with a blind brown dog. which statements are true about this scenario? check all that apply.

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Jovanni

26 December, 16:09

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Braeden Atkinson · Answer 1

Ans : BbNn x bbnn - gives:

In a ratio of 1; 1:1:1

BbNn - 1/4 black normal

Bbnn - 1/4 black blind

bbNn - 1/4 brown normal

bbnn - 1/4 brown blind