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19 January, 10:47

A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:

p^2 + 2pq+q^2=1

f (HH) = p2 =

f (Hh) = 2pq =

f (hh) = q2 =

+3
Answers (2)
  1. 19 January, 11:00
    0
    HH. 04

    Hh. 16

    hh -.64

    i think
  2. 19 January, 11:35
    0
    f (HH) = p 2 = 0.04

    f (Hh) = 2pq = ⇒ 0.32,.32

    f (hh) = q 2 = ⇒ 0.64,.64
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