• Biology Biology

A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:

p^2 + 2pq+q^2=1

f (HH) = p2 =

f (Hh) = 2pq =

f (hh) = q2 =

Answers (2)
  1. Melita
    HH.04

    Hh.16

    hh - .64

    i think
  2. Saiya
    f (HH) = p 2 = 0.04

    f (Hh) = 2pq = ⇒ 0.32,.32

    f (hh) = q 2 = ⇒ 0.64,.64
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