In recessive lethal diseases such as tay-sachs disease, carriers have one copy of the normal allele and one copy of the allele for the disease. carriers are represented in the hardy-weinberg formula by

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Biology

Howie

7 December, 05:03

In recessive lethal diseases such as tay-sachs disease, carriers have one copy of the normal allele and one copy of the allele for the disease. carriers are represented in the hardy-weinberg formula by

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Eva Zhang · Answer 1

The hardy weinberg formula is: p2 + 2pq + q2 = 1 Homozygous dominant (healthy) is represented by p2 while homozygous recessive (diseased) is represented by q2. This leaves 2pq as the heterzygous carrier, as it has one p allele and one q allele.