A woman can read the large print in a newspaper only when it is at a distance of 67 cm or more from her eyes. (a) is she nearsighted (myopic) or farsighted (hyperopic), and what kind of lens is used in her glasses to correct her eyesight? (b) what should be the refractive power

(a) As women is able to see a distance of 67 cm or more from her eyes.

so, she has difficulty reading close objects.

So she is

farsighted (hyperopic)

To correct her eyesight converging lens or convex lens will be used.

(b) u = 24 cm - 2.3 cm = 21.7 cm

v = - 67+2.3 = 64.7 cm

1/v+1/u = 1/f

1/f = 0.03063

f=32.651 cm

Power = 100/f = + 3.0627