The internal solute concentration of a plant cell is about 0.8M. To demonstrate plasmolysis, it would be necessary to suspend the cell in what solution?

In hypertonic solution with high solute concentration than the plant cell that is about 1.0 M

Explanation:

The tonicity of the cell is determined by placing the cells in an either hypotonic, hypertonic or isotonic solution.

The plasmolysis refers to the process taking place in the plant cell which allows the movement of the water out of the cell through the process of osmosis which leads to the shrinkage of the cytoplasm.

The cytoplasm shrinks when the cell is placed in the hypertonic solution which contains a high amount of solute than the plant cell and therefore less amount of water. As a result of this, the water moves out from the cell to the solution down their concentration gradient from high to a low level.

Thus, In hypertonic solution with high solute concentration than the plant cell that is about 1.0 M is the correct answer.