Place the events in order of sympathetic motor pathway. 1. postganglionic neuron depolarizes 2. acetylcholine binds to sweat gland's muscarinic receptor 3. postganglionic neuron releases acetylcholine 4. neuron exits lumbar segment of spinal cord 5. acetylcholine binds to nicotinic receptor 6. neuron releases acetylcholine

Answer: 1, 3, 5, 2, 6, 4

Explanation:

The sympathetic nervous system stimulates many parts of the body for action during times of danger.

This signalling starts when the postganglionic neuron depolarizes, and postganglionic neuron releases acetylcholine, then the acetylcholine binds to nicotinic receptor in order to transmit impulse, and further the acetylcholine binds to sweat gland's muscarinic receptor to disrupt or inactivate the action of acetylcholine. Finally, the neuron releases acetylcholine, and the neuron exits lumbar segment of spinal cord.

The danger has now been fully interpreted.