For linked genes A, B, and C, the map distance A-B is 5 map units and the map distance B-C is 25 map units. If there are 10 double crossover events out of 1000 offspring, what is the interference?

Question

Biology

Patrick Fuller

8 August, 18:55

For linked genes A, B, and C, the map distance A-B is 5 map units and the map distance B-C is 25 map units. If there are 10 double crossover events out of 1000 offspring, what is the interference?

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Answers (1)

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Saige · Answer 1

0.2

Explanation:

Given:

Distance between A-B = 5 map unit,

Distance between B-C = 25,

The value of coefficient of coincidence is = 0.01/0.0125 = 0.8,

so the interference is 1 - 0.8 = 0.2.

The positive value of interference confirms that the genes are linked, if it value is negative, then shows that the genes are unlinked