How many grams of CaCl2 are in 0.75M solution with a volume of 1L

83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.

Explanation:

Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.

let us find the number of moles

n=C*V Concentration is 0.75M

Volume is 1000ml.

n = 0.75*1

n = 0.75

This means there are 0.75 moles of CaCl2 in 1000 ml of solution of. 75M.

Molar mass of CaCl2 is = 40.08 + 2 (35.5)

= 110.98 gms

Thus 1 MOLE OF CaCl2 weighs 110.98

so 0.75 moles will weigh 110.98*0.75

= 83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.