Consider a cross between individuals that are: AaBbCcDd and AAbbccDD in which all genes segregate independently. What frequency of progeny will have the same genotype as the AAbbccDD parent?

1/16

Explanation:

The genotype of parents: AaBbCcDd and AAbbccDD

To calculate the frequency of a child with a specific genotype, we can calculate the individual frequencies for each gene and apply the product rule to calculate the overall frequency.

Aa x AA = 1/2 Aa: 1/2 AA

Bb x bb = 1/2 Bb: 1/2 bb

Cc x cc = 1/2 Cc: 1/2 cc

Dd x DD = 1/2 DD: 1/2 Dd

Therefore, the frequency of a progeny with genotype AAbbccDD = 1/2 AA x 1/2 bb x 1/2 cc x 1/2 DD = 1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 0.0625.