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27 June, 05:28

If a population with two alleles is at Hardy-Weinberg equilibrium ad the frequency of one allele is 0.7, what is the heterozygote frequency?

A. 0.7B. 0.42C. 0.3D. 0.21E. insufficient information given to answer the question

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  1. 27 June, 07:45
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    B. 0.42

    Explanation:

    Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1

    According to the given information, the frequency of one allele in the population is = 0.7

    This means that the frequency of the other allele would be = 1-0.7 = 0.3

    Frequency of heterozygote in the population = 2pq = 2 x 0.7 x 0.3 = 0.42
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