A segment of a gene contains 27 nucleotides, none of which include stop or start codons. How many amino acids does this segment code for?

Group of answer choices

9 amino acids

81 amino acids

27 amino acids

3 amino acids

Question

Biology

Guest

10 June, 09:49

A segment of a gene contains 27 nucleotides, none of which include stop or start codons. How many amino acids does this segment code for?

Group of answer choices

9 amino acids

81 amino acids

27 amino acids

3 amino acids

+3

Answers (1)

Know the Answer?

Bender · Answer 1

If none of the nucleotides includes stop or start codons when a segment of a gene contains 27 nucleotides there will be 81 amino acids in this segment code.

Answer: Option B

Explanation:

Codon is a nucleotides within messenger RNA. A stop or start codon is a nucleotide triplet which signals protein termination. Start codons initiate to start translation while the stop codon initiates termination.

The genetic codes are the sequence for nucleotide that codes for amino acids. A segment containing 27 nucleotides multiplied by 3 gives 81 amino acids. Every nucleotide in an mRNA are read "three at a time". Hence this segment codes for 81 amino acids.

A segment of a gene contains 27 nucleotides, none of which include stop or start codons. How many amino acids does this segment code for?Group of answer choices9 amino acids81 amino acids27 amino acids3 amino acids

A segment of a gene contains 27 nucleotides, none of which include stop or start codons. How many amino acids does this segment code for?

Group of answer choices

9 amino acids

81 amino acids

27 amino acids

3 amino acids