Tongue rolling is dominant over no tongue rolling in humans. Colorblindness is X-linked recessive.

So, if a normal tongue-rolling (heterozygous) male breeds with a carrier tongue-rolling (heterozygous) female, what would the offspring be?

The correct answer would be -

50% of offspring would be tongue rolling (heterozygous) and 50% would be non-tongue rolling.

for color blindness, offspring would be 25% carrier female, 25% diseased male, 25% normal female, and 25 % normal male.

In this case of breeding the male is normal tongue rolling (Rr/XY) and female is carrier tongue rolling (rr/XXc). The carrier is the condition when a female has only one copy of the mutated allele. The tongue rolling is an autosomal condition.

Thus, the correct answer is -

50% of offspring would be tongue rolling (heterozygous) and 50% would be non-tongue rolling.

for color blindness, offspring would be 25% carrier female, 25% diseased male, 25% normal female, and 25 % normal male.