How many grams of CaCl2 are needed to make3.5L (3500ml)

of a 15% calcium chloride solution?

525 grams

Explanation:

Assuming the solution to be prepared is 15% by weight calcium chloride, it means 15 grams of calcium chloride will be in 100 mL of solution.

To calculate the amount needed to make 3500 mL solution;

15 g is required to make 100 mL

X g is required to make 3500 mL

X = 15 x 3500/100

= 525 g

Therefore, 525 grams of calcium chloride will be needed to make 15%, 3500 mL of calcium chloride solution.