Ask Question
14 September, 20:02

Two brothers have X‑linked red-green colorblind vision, and their parents have normal color vision. The first brother's karyotype is 47, XXY (Klinefelter syndrome), and the second brother's karyotype is 46, XY. In which parent and in what cell division phase did the first brother's chromosomal nondisjunction occur? Assume no recombination.

(A) in the father in meiosis I

(B) in either parent in somatic cell mitosis

(C) in the father in meiosis II

(D) in the mother in meiosis II

(E) in the mother in meiosis I

+3
Answers (1)
  1. 14 September, 23:42
    0
    The correct answer is option C, that is, in the mother in meiosis II.

    Explanation:

    A nondisjunction in meiosis I produce all the aneuploid gametes, while nondisjunction at meiosis II produces 50 percent aneuploid gametes and the 50 percent normal gametes comprising haploid number of chromosomes.

    As it is mentioned that one of the brothers possess normal number of chromosomes (46), the mother encounters nondisjunction at meiosis II resulting in the formation of one n+1 gamete exhibiting two copies of X chromosome. Fertilization of this n+1 gamete with sperm results in the creation of zygote (47, XXY).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two brothers have X‑linked red-green colorblind vision, and their parents have normal color vision. The first brother's karyotype is 47, ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers