A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it

conveyor belt?

40 J

80 3

160 J

1,600)

K. E = 80 j

Explanation:

Given dа ta:

Mass of box = 40 Kg

Velocity = 2 m/s

K. E = ?

Solution:

K. E = 1/2 m. v²

K. E = 1/2 (40 Kg) (2 m/s) ²

K. E = 1/2 (40 Kg) (4m²/s²}

K. E = 1/2 (160 Kg. m²/s²)

K. E = 80 Kg. m²/s²

Kg. m²/s² = j

K. E = 80 j