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20 July, 08:43

In horses, the gene for black coat color is dominant over the gene for brown coat color. The gene for long manes is dominant over the gene for short manes. After a cross is made between a homozygous black, long mane mare (BBLL) and a stallion homozygous for brown color and short mane (bbll), and the F1 offspring are interbred, the expected outcome in the F2 for a brown, long mane horse would be

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  1. 20 July, 12:00
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    3/16

    Explanation:

    Given,

    Black coat color is dominant over brown coat color.

    Long mane is dominant over short mane.

    BBLL X bbll =

    F1: BbLl = Entire progeny has black color and long mane

    BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,

    BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1

    3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.
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