A 5.0-g egg falls from a 90-cm-high counter onto the floor and breaks. What impulse is exerted by the floor on the egg?

0.021 kgm/s

Explanation:

using energy

change potential energy of the egg = change in kinetic energy of the egg

mgh = 1/2 mv² m in kg, h in meters

5.0g = 5.0/1000 kg = 0.005 kg

90 cm = 90 / 100 = 0.9 m

cancel m on both side

gh = 1/2 v²

make v subject of the formula

v = √2gh = √2*9.81*0.9 = √17.658 = 4.2 m/s that is the velocity of the egg on impact with floor and the initial velocity of the egg is zero.

impulse = m * Δv = 0.005 * 4.2 = 0.021 kgm/s