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22 June, 17:03

The ability to taste the chemical phenylthiocarbamide is an autosomal dominant phenotype, and the inability to taste it is recessive. If a taster woman with a nontaster father marries a taster man who in a previous marriage had a nontaster daughter, what is the probability that their first child will be:

a. a nontaster girl?

b. a taster girl?

c. a taster boy

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  1. 22 June, 19:33
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    a. a nontaster girl = 1/8

    b. a taster girl = 3/8

    c. a taster boy = 3/8

    Explanation:

    Let's assume that the allele "T" is responsible for the taster phenotype while the recessive allele "t" gives the nontaster phenotype. The taster woman had a nontaster father (tt). Therefore, she is heterozygous dominant (Tt). The taster man had a nontaster daughter (tt) which means that he also has one "t" allele and his genotype is "Tt".

    A cross between Tt and Tt would produce progeny in following ratio=

    Tt x Tt = 3/4 taster: 1/4 nontaster

    The probability of sons and daughters during each reproduction is=

    XX x XY = 1/2 XX and 1/2 XY

    Therefore,

    a. probability of having a nontaster girl = 1/4 x 1/2 = 1/8

    b. a taster girl = 3/4 x 1/2 = 3/8

    c. a taster boy = 3/4 x 1/2 = 3/8
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