Ask Question
6 June, 00:52

Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places) ?

+1
Answers (1)
  1. 6 June, 01:02
    0
    0.00498

    Explanation:

    The equilibrium frequency can be calculated by the formula as follows:

    qe = u / (u + v)

    Here, qe is equilibrium frequency, u = 0.00005 = the forward mutation rate and v is the backward mutation rate = 0.01.

    qe = 0.00005 / (0.00005 + 0.01) =

    qe = 0.00498.

    Thus, the answer is 0.00498.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers