 Biology
6 June, 00:52

# Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places) ?

+1
Answers (1)
1. 6 June, 01:02
0
0.00498

Explanation:

The equilibrium frequency can be calculated by the formula as follows:

qe = u / (u + v)

Here, qe is equilibrium frequency, u = 0.00005 = the forward mutation rate and v is the backward mutation rate = 0.01.

qe = 0.00005 / (0.00005 + 0.01) =

qe = 0.00498.

Thus, the answer is 0.00498.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Mutation at this locus changes one allele to the other (i. e. it does not create a new allele). If the rate of mutation from allele 1 to ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.