Ask Question
18 April, 02:27

Previous genetic linkage crosses have determined that recombination frequencies are 6% for genes A and B, 4% for genes B and C, 10% for genes C and D, and 11% for genes D and E. The sum of these frequencies between genes A and E is 31%. Why does the recombination distance between these genes as determined by adding the intervals between adjacent linked genes differ from the distance determined by the test cross?

+1
Answers (1)
  1. 18 April, 02:59
    0
    Because as distance between genes increase, the probability of one recombination grows, but the probability of two recombinations occuring also increases

    Explanation:

    If we only score the outcome as yes or no to recombination between two genes, then one recombination is a yes, but two is a no and three is a yes again (and so on).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Previous genetic linkage crosses have determined that recombination frequencies are 6% for genes A and B, 4% for genes B and C, 10% for ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers