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1 June, 00:07

If a woman is a carrier for the color-blind recessive allele and her husband is normal, what are their chances that a son will be color-blind?

a. None since the father is normal.

b. 50% since the mother is the only carrier.

c. 100% because the mother has the gene.

d. 25% because the mother is a hybrid.

e. None since he will also be just a carrier.

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  1. 1 June, 04:04
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    b. 50% since the mother is the only carrier.

    Explanation:

    Color blindness is a X linked recessive trait characterized by difficulty in differentiating between some colors. Let us assume

    C = dominant allele

    c = recessive allele

    Given,

    mother is a carrier = XCXc

    father is normal = XCY

    Hence their children: XC Xc

    XC XCXC XCXc

    Y XCY XcY

    The sons can either be XCY (normal) or XcY (color blind). Hence they have half or 50% chance to be colorblind since half of the sons will get one recessive allele from the carrier mother.
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