In goats, a recessive gene causes the goats to "faint" when they are startled. A farmer has a goat that is a carrier for the fainting gene (Gg). Gertrude is mated with one that is homozygous dominant. How many of their offspring will be fainters

None

Explanation:

This question states that this particular allele (dubbed "g") acts in a recessive manner. This means that the corresponding "fainter" phenotype will be found only when the allele is present in a homozygote state (gg).

If a Gg (heterozygous) goat is mated with a GG (homozygous dominant) goat, it would be expected that approximately 50% of their progeny will be GG and the other 50% will be Gg. Barring the occurrence of de novo mutations, one would not expect any of the offspring to possess an homozygous recessive (gg) genotype and therefore develop as "fainters".

None

Explanation:

A cross between a heterozygous goat and a homozygous dominant goat would result in no children having the trait.

G G

G GG | GG

- - | - -

g Gg | Gg