Ask Question
13 March, 16:49

A geneticist is mapping the chromosomes of the newly captured gremlin. Stripe is heterozygous for three linked genes with alleles Ee, Hh, and Bb, that determine if gremlins are evil (E), have hair (H), and biting teeth (B). In order to determine if the 3 genes were linked, a standard testcross was done, and the 1000 offspring had the following genotypes: 48 ee Hh bb 36 ee hh Bb 400 ee Hh Bb 4 Ee Hh Bb 426 Ee hh bb 46 Ee hh Bb 38 Ee Hh bb 2 ee hh bbChoose the alleles on the homologous chromosomes of the heterozygous individuals with the correct gene order. What is the recombination frequency between genes E and B? a. 8.4% b. 9.0% c. 42.6% d. 9.4% e. 10.0%

+2
Answers (2)
  1. 13 March, 16:56
    0
    A geneticist is mapping the chromosomes of the newly captured gremlin. Stripe is heterozygous for three linked genes with alleles Ee, Hh, and Bb, that determine if gremlins are evil (E), have hair (H), and biting teeth (B). In order to determine if the 3 genes were linked, a standard testcross was done, and the 1000 offspring ...
  2. 13 March, 17:27
    0
    The correct gene order is H-e-B

    Recombination frequency between genes E and B = 10%

    Explanation:

    In linkage parental genotype is always in greater number than recombinants, hence:

    400 = eeHhBb : Parental

    426 = Eehhbb : Parental

    Double crossovers have the smallest number hence:

    EeHhBb = 4 : Double recombinant

    eehhbb = 2 : Double recombinant

    Double cross over places middle allele from one sister chromatid to other one. Hence a non parental allele of the middle gene is present with parental alleles of the flanking genes.

    Here recombinant type is EHB and parental type is eHB. Only gene order H-e-B would result in double cross over which would give EHB and ehb double recombinants. Hence, the correct gene order is H-e-B.

    Single crossover between gene E and B would result in Heb and hEB progeny (48 and 46)

    Recombination frequency between E and B = [ (Double recombinants + Single E and B recombinants) / Total progeny) * 100]

    = [ (4 + 2 + 48 + 46) / 1000] * 100

    = 100/1000

    = 0.1 * 100 = 10%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A geneticist is mapping the chromosomes of the newly captured gremlin. Stripe is heterozygous for three linked genes with alleles Ee, Hh, ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers