suppose you found a bone of a mastodon which had 6.25%c14and93.75%n14 how long ago did this animal die

t = 3886.18 years old

Explanation:

Whenever an animal dies de C14 and N14 begin to disintegrate in such a way that the proportion between C14 and C12 decreases, with a semi-disintegration period of 5.730 years, T. To get to know how long it takes an element to disintegrate, we must use this semi-disintegration period, which is the time it takes until the amount of the element is reduced to its half.

We can find the age of the fossil, t, by using the next formula:

t = - (T x ln (C14)) / ln (2)

t = - (5730 x ln (0.625) / 0.693

t = - (-2693.12) / 0.693

t = 3886.18