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17 July, 18:13

Select the correct answer.

A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?

A.

(0.70) * (0.30)

B.

(0.70) - (0.30)

C.

2 * (0.70) * (0.30)

D.

2 * (0.70 - 0.30)

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Answers (1)
  1. 17 July, 21:58
    0
    the frequency of heterozygous = 2 * 0.7 * 0.3

    Explanation:

    therefore it is answer c
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