The double-stranded DNA molecule of the newly discovered Elradicus libanii has a length of 34 micrometers. How many base pairs are present in this molecule?

100 000

Explanation:

The average length of a base pair (bp) is 340 pm [340 * 10^ (-12) m]

Length of DNA = No. of bp * length of bp

34 * 10^-6 m = n * 340 * 10^-12 m

n = (34 * 10^-6) / (340 * 10^-12) = 100 000

The DNA molecule contains 100 000 base pairs.