Ask Question
2 August, 03:47

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?

A. 72.25 percent

B. 2.25 percent

C. 12.75 percent

D. 25.5 percent

+1
Answers (2)
  1. 2 August, 04:33
    0
    A. 72.25 percent

    Explanation:

    The frequency of a genotype is calculated by the product of multiplying allele frequencies.

    The R allele has a frequency of 85% (0.85), so for a homozyguous individual RR:

    f (R) * f (R) = 0.85 * 0.85 = 0.7725

    0.7725 * 100 = 77.25%

    It is concluded that the frequency for RR genotype is 77.25%.
  2. 2 August, 06:47
    0
    A. Since the frequency of the R allele is 0.85, the frequency of the RR genotype would be 0.85^2 = 0.7225.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is ...” in 📘 Biology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers