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20 February, 08:25

Both a man and a woman are heterozygous for freckles. Freckles (F) are dominant over no freckles (f). What is the chance that their child will have freckles?

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  1. 20 February, 09:38
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    75% chance or 3/4

    Explanation:

    If both parents are heterozygous and freckles is a dominant trait (F) then we can denote having no freckles as (f)

    Using a punnett square, this will produce the following genotypes of the children:

    FF, Ff, Ff and ff.

    Therefore, there's a 3 out 4 chance or 75% of the children also inheriting freckles.
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