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17 January, 17:39

A heterozygous right handed mom and a homozygous left handed dad (recessive) mate. What percent of children are expected to be left handed?

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  1. 17 January, 18:31
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    50% chance will left handed.

    Explanation:

    Right handed = dominant (R)

    Left handed = recessive (r)

    Heterozygous right handed mom = Rr

    Homozygous left handed dad = rr

    According to punnett's square:

    Rr x rr

    =2/4 Heterozygous (Rr)

    = 2/4 homozygous recessive (rr)

    So, there will be 50 % or 2/4 chance of left handed children.
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