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16 May, 06:13

A man who has pattern baldness married a woman who is a carrier for the trait. What percent of their male children would be expected to develop male pattern baldness as adults?

A 25%

B 0%

C 50%

D 100%

+3
Answers (1)
  1. 16 May, 10:13
    0
    C. 50%

    Explanation:

    Baldness is sex-linked, so we need to use the X and Y chromosome notation. Let's represent baldness with B, and no baldness as b.

    Man: XB Y

    Woman: XB Xb

    (Remember, she's a carrier: so she has one B allele, but not both, otherwise she would express the trait.)

    What's next - Punnett square, our old buddy:

    XB Y

    XB XB XB XB Y

    Xb XB Xb Xb Y

    So out of that square, they've got two males. That's our denominator. And it wants to know how many male progeny will be bald: that's only one, the one with XB Y. He will express the B allele because the Y's kinda just like a placeholder. So the probability is 50%.
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