if a cubical cell with with 2 cm sides doubles the dimensions of its sides what change occurs to the ratio of its surface area to volume

The surface area of a cell is 6 * side² and volume of a cubical cell is side³.

Surface area of cell having side 2 cm = 6 * 2 * 2 = 24 cm²

volume of the cell = 2 * 2 * 2 = 8 cm³

Therefore, surface area to volume ration is 24:8 = 3 : 1

If the side of a cell is doubled, then

Surface area of cell = 6 * 4 * 4 = 96 cm²

volume of the cell = 4 * 4 * 4 = 64 cm³

Therefore, surface area to volume ration is 96 : 64 = 3 : 2

Surface area to volume ratio decreases.