A woman homozygous for polydactyly (extra fingers and toes), a dominant trait, is married to a man with 5 fingers and toes. Enter in the box below, the percentage (between 0 - 100) of the offspring of this couple that would be expected to be polydactytl.

Question

Biology

Gage Hobbs

29 March, 08:55

A woman homozygous for polydactyly (extra fingers and toes), a dominant trait, is married to a man with 5 fingers and toes. Enter in the box below, the percentage (between 0 - 100) of the offspring of this couple that would be expected to be polydactytl.

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Samson · Answer 1

100%

Explanation:

Assuming the gene for polydactyly is represented by P. Normal finger will be represented by p.

A woman that is homozygous for polydactyly trait will have genotype PP while a man with normal 5 fingers and toes will have the genotype pp (since P is dominant over p).

PP x pp = Pp, Pp, Pp and Pp.

All the offspring will have the genotype Pp and since P is dominant over p, it means all the offspring will have polydactyly trait.

Hence, the percentage of the offspring of the couple that would be expected to be polydactyly is 100%