Two positive integers are 3 units apart on a number line. Their product is 108.

Solve for m, the greater integer, using which of the equation below?

m (m - 3) = 108

A. m (m + 3) = 108

B. (m + 3) (m - 3) = 108

C. (m - 12) (m - 9) = 108

The first integer as given in the question = m

Then

The second integer as described in the question = m + 3

Then the equation will be

m (m + 3) = 108

The correct option is option "A".

Now let us solve for "m"

m^2 + 3m - 108 = 0

m^2 + 12m - 9m - 108 = 0

m (m + 12) - 9 (m + 12) = 0

(m + 12) (m - 9) = 0

So the value of "m" is - 12 and 9.