A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

Question

Biology

Johnston

26 November, 15:59

A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

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Answers (1)

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Mathew Ayers · Answer 1

The answer is 314.6 K

Gay-Lussac’s law:

PV = kT

P - pressure

V - volume

T - temperature

k - constant

k = PV/T = P1 * V1 / T1 = P2 * V2 / T2 = ...

P1 * V1 / T1 = P2 * V2 / T2

P1 = 1.1 atm

V1 = 7 L

T1 = 285 K

P2 = 1.1 atm - 0.6 atm = 0.5 atm

V2 = 7 L + 10 L = 17 L

T2 = ?

1.1 * 7 / 285 = 0.5 * 17 / T2

7.7 / 285 = 8.5 / T2

T2 = 8.5 * 285 / 7.7

T2 = 314.6 K