Find the amount of work done in emptying a cylindrical tank completely filled with kerosene. Assume that the radius of the cylindrical tank is 3 m, height is 6 m, and the density of kerosene is 817.15 kg/m3

The formula for the work done in emptying a tank is this:

W = ωyV

where

ω is the specific weight

y is the center of gravity

V is the volume of the liquid

The specific weight can be calculated using the formula

ω = ρg

where

ρ is the density

g is the acceleration due to gravity

Solving for ω

ω = 817.15 kg/m3 (9.81 m/s2)

ω = 8016.24 N/m3

The center of gravity of a completely filled cylindrical tank is just 1/2 of the height. So,

y = 3 cm

The volume of the kerosene is just the volume of tank. Using the formula for the volume of a cylinder

V = πr²h

V = π (3²) (6)

V = 54π m³

Therefore, the word done is

W = 8016.24 (6) (54π)

W = 8159538.47 J or

W = 8.16 MJ