A store is creating a 18 lb mixture of chocolates and nuts. chocolates cost $3.00 per pound, and nuts cost $1.50 per pound. the store wants to make a mixture that costs, on average, $2.00 per pound. how many pounds of nuts are needed for this mixture?

Question

Business

Brayden Sampson

31 March, 19:27

A store is creating a 18 lb mixture of chocolates and nuts. chocolates cost $3.00 per pound, and nuts cost $1.50 per pound. the store wants to make a mixture that costs, on average, $2.00 per pound. how many pounds of nuts are needed for this mixture?

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Answers (1)

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Gregory Peck · Answer 1

We will make 2 equations where:

C - chocolate

N - nuts

C + N = 18

3 C + 1.5 N = 2 (N + C)

3 C + 1.5 N = 2 N + 2 C

3 C - 2 C = 2 N - 1.5 N

C = 0.5 N (we will put it into the 1st equation)

0.5 N + N = 18

1.5 N = 18

N = 18 : 1.5

N = 12 lb.

Answer: 12 pounds of nuts are needed for this mixture.