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14 March, 01:35

Ms. jamison plans to invest $3,800 in two accounts for one year. the first account earns a yearly interest of 3.5%. the second account earns a yearly interest of 6%. how much money does ms. jamison need to invest in the second account in order to earn $188 in interest from both accounts?

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  1. 14 March, 02:54
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    0.035x+0.06 (3800-x) = 188

    Solve for x

    0.035x+228-0.06x=188

    0.035x-0.06x=188-228

    -0.025x=-40

    X=40/0.025

    X=1600. Invested at 3.5%

    3800-1600=2200 invested at 6%
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