The quadratic function f (x) = 2x^2-24x+c has two zeros that differ by 18. Find the value of c.

For this case we have the following function:

f (x) = 2x ^ 2-24x + c

We set zero to find the roots of the function.

We have then:

2x ^ 2-24x + c = 0

x ^ 2-12x + c / 2 = 0

Factoring we have:

(x - / + x1) (x - / + x2) = 0

On the other hand we have:

x2-x1 = 18

x2 + x1 = - 12

Solving the system we have:

x1 = - 15

x2 = 3

Substituting we have:

(x-15) (x + 3) = 0

Rewriting:

x ^ 2 - 12x - 45 = 0

Therefore, the value of c is given by:

c / 2 = - 45

c = - 90

Answer:

the value of c is:

c = - 90