A person invested $20,000 into two accounts that pays 2.5% and 3% simple interest annually, respectively. find the amount invested into the two accounts if the total interest earned after one year is $540

Let:

x = amount in the account invested in 2.5%

20000 - x = amount in the account invested in 3%

Solution:

.025x +.03 (20000 - x) = 540

.025x + 600 -.03x = 540

-.005x + 600 = 540

-.005x = 540 - 600

-.005x = - 60

x = 12000

Therefore, that person invests 12,000 at 2.5%

and

20,000 - 12,000 = 8,000 at 3%