Ask Question
5 May, 10:54

American energy review reported that 27% of american households burn wood. if a random sample of 500 american households is selected find the mean, variance, and standard deviation of the number of households that burn wood.

+5
Answers (1)
  1. 5 May, 12:58
    0
    This is binomial distribution problem.

    We are given that:

    n = sample size = 500

    p = proportion which burns wood = 0.27,

    q = proportion which does not burn wood = 1-p = 0.73

    A. Mean is calculated as:

    Mean = n*p

    Mean = 500 * 0.27

    Mean = 135

    B. Variance is calculated as:

    Variance = n*p*q

    Variance = 500*0.27*0.73

    Variance = 98.55

    C. Standard deviation is calculated as:

    Standard deviation = sqrt (variance)

    Standard deviation = sqrt (98.55)

    Standard deviation = 9.93
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “American energy review reported that 27% of american households burn wood. if a random sample of 500 american households is selected find ...” in 📘 Business if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers