A theater group made appearances in two cities. The hotel charge before tax is the second city was $ 1000 higher than in the first. The tax in the first city was 8.5 % and the tax in the second city was 5.5 %. The total hotel tax paid for the two cities was $ 790. How much was the hotel charge in each city before tax?

First city was = $ x = $ 5604

Second city was = $ (x + 1000) = $6604

Explanation:

The tax in the first city was 8.5%

The tax in the second city was 5.5%

Let the hotel charge amount before tax for the first city be $x

Let the hotel charge amount before tax for the second city be: $ (x+1000)

Applying the tax

First city will be;

8.5/100 * (x) = $0.085 x

Second city will be;

5.5/100 * (x+100) = 0.055 (x+100) = $ (0.055x+5.5)

Total hotel tax paid for the two cities was;

0.085 x + 0.055 x + 5.5 = $ (0.14 x + 5.5)

This expression for total hotel tax paid for the two cities is equal to $790

$ (0.14 x + 5.5) = $ 790

0.14 x = 790 - 5.5

0.14 x = 784.5

x = 784.5/0.14

x=5603.57

x = $5604 (nearest $)

Before tax, hotel charge for;

First city was = $ x = $ 5604

Second city was = $ (x + 1000) = $6604