A hat contains 6 red balls, 4 yellow balls, and 2 green balls. If you draw a red ball, you lose $5. If you draw a yellow ball, you win $1. If you draw a green ball, you win $7. What is the expected profit of one draw? Round your answer to the nearest cent. Enter an expected loss as a negative number.

- $1 (negative one dollar)

Explanation:

For each instance multiply the profit of drawing a particular color by probability.

Then add the vales to get expected amount on one draw.

Total balls = 12

For red ball if you draw, you will lose $5, so = - 5 * (6/12) = - 5 * (1/2) = - 2.5

For yellow balls you gain $1, so = 1 * (4/12) = 1 * (1/3) = 0.333333

For green balls you gain $7, so = 7 * (2/12) = 7 * (1/6) = 1.166666

So amount on one draw = - 2.5+0.3333333+1.1666666 = - $1