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30 August, 11:21

A beer distributor finds that it sells on average 1000 cases a week of regular 12-oz. Budweiser. For this problem assume that demand occurs at a constant rate over a 50-week year. The distributor currently purchases beer at a cost of $8 per case. The inventory-related holding cost (capital, insurance, etc.) for the distributor equals 25% of the value of inventory per year. Each order placed with the supplier costs the distributor $10. What order quantity minimizes the distributor's total costs?

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  1. 30 August, 14:59
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    D = 1,000 x 50

    Co = $10

    H = 25% x $8 = $2

    EOQ = √2 x 50,000 x $10/2

    EOQ = √500,000

    EOQ = 707 units

    Explanation: In the above calculation, D represents annual demand, which is weekly demand multiplied by 50 weeks. Co denotes ordering cost and H is the holding or carrying cost, which is 25% of the cost price. Thus, EOQ is the square root of 2 x annual demand x ordering cost divided by holding cost. EOQ is the quantity that minimises the total cost.
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